amberhong2006 amberhong2006

10-05-2018
Mathematics

contestada

what is the 2012th sequence of 11,21,31,41

Respuesta :

geerky42 geerky42

10-05-2018

First term is 11. You get second term by adding 10 to first term, and so on.

So nth term would looks like a(n) = 11 + 10(n-1)

So then 2012th term would be 11 + 10(2012-1) = 11 + 20110 = 20121

Hope this helps.

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good job