Respuesta :

[tex] \frac{4m-17}{m^{2}-16} + \frac{3m - 11}{m^{2}-16} = \frac{4m-17+3m - 11}{m^{2}-16} = \frac{7m-28}{m^{2}-16} = \frac{7(m-4)}{(m-4)(m+4)} = \frac{7}{m+4} When (m-4) \neq 0 , m \neq 4.[/tex]
1rstar

[tex] \dfrac{4m - 17}{ {m}^{2} - 16 } + \dfrac{3m - 11}{ {m}^{2} - 16 } \\ \\ = \: \dfrac{7m - 28}{ {m}^{2} - 16 } \: \: = \: \: \frac{7(m - 4)}{(m + 4)(m - 4)} \\ \\ = \: \: \frac{7}{m + 4} \: \: (where \: m \: is \: not \: equal \: to \: 4)[/tex]
good job