TeslaElectric
TeslaElectric TeslaElectric
  • 07-07-2018
  • Mathematics
contestada

On a(n) 16-problem test, how many ways can a person get 6 problems correct and 10 problems wrong?

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ASIAX
ASIAX ASIAX
  • 07-07-2018
Hi there!

Using the formula 

[tex]C(n, r) = \frac{n!}{(r!(n-r)!)} [/tex] 

n = # of objects
r = the sample of objects

Plug in 16 for n and 6 for r to get

[tex]C(16, 6) = \frac{16!}{(6!(16-6)!)} [/tex] 

Now solving this equation will give you 8008 combinations as your answer.

Your friend, ASIAX
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