[tex] f(x)=\dfrac{x^2-4}{x^2-6x+8}=\dfrac{x^2-2^2}{x^2-4x-2x+8}=\dfrac{(x-2)(x+2)}{x(x-4)-2(x-4)}\\\\=\dfrac{\boxed{(x-2)}(x+2)}{\boxed{(x-2)}(x-4)}\to x=2\\\\g(x)=\dfrac{x+2}{x-4}\to g(2)=\dfrac{2+2}{2-4}=\dfrac{4}{-2}=-2\to y=-2\\\\\text{Answer:}\ b.\ (2,\ -2) [/tex]
