For the given table, the difference between two consecutive y terms are
[tex]4-3=5-4=6-5=7-6=1[/tex]
It means the difference is constant. So the given function is in arithmetic progression.
And to find the equation, representing the given series, we will use the formula for the nth term of arithmetic series, which is
[tex]a_{n}= a+ (n-1)d[/tex]
Here,
[tex]a_{n} =y, n=x, and \ d \ for \ the \ common \ difference.[/tex]
So we will get
[tex]y= 3+(x-1)(1)
\\
y = 3 + x-1
\\
y= x +2[/tex]
