keilyme182 keilyme182

07-10-2018
Mathematics

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Answer question please

Answer question please class=

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jimrgrant1 jimrgrant1

07-10-2018

∠EFH = 6y + 14

since HF bisects ∠GFI then ∠GFH = ∠HFI = 2y + 6

hence ∠EFH = ∠EFG + ∠GFH = 4y + 8 + 2y + 6 = 6y + 14

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