[tex]\frac{2x}{x + 3} - \frac{3}{x - 4}[/tex]
The LCM of x+3 and x-4 is x² - x - 12
Working out gives;
[tex]\frac{2x^2 - 8x - 3x - 9}{x^2 - x - 12} = \frac{2x^2 - 11x - 9}{x^2 - x - 12}[/tex]
Simplify further using equations calculator to get the answer as attached below:
