Respuesta :

gmany

[tex]z^{\frac{14}{5}}\cdot z^{-\frac{4}{5}}=z^{\frac{14}{5}+\left(-\frac{4}{5}\right)}=z^{\frac{14-4}{5}}=z^{\frac{10}{5}}=z^2\\\\Used:\ a^n\cdot a^m=a^{n+m}[/tex]

Otras preguntas

good job