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06-11-2018
Mathematics

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06-11-2018

The point-slope form:

[tex]y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

We have the point (8, -6) and the slope m = [tex]-\dfrac{5}{6}[/tex].

Substitute:

[tex]y-(-6)=-\dfrac{5}{6}(x-8)\\\\\boxed{y+6=-\dfrac{5}{6}(x-8)}[/tex]

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