Respuesta :

gmany

The point-slope form:

[tex]y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

We have the point (-2, -6) and the slope m = [tex]\dfrac{1}{3}[/tex].

Substitute:

[tex]y-(-6)=\dfrac{1}{3}(x-(-2))\\\\\boxed{y+6=\dfrac{1}{3}(x+2)}[/tex]

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