Solution:
The given function is,
y=x(x-2)(x+3).
It is a cubic polynomial, whose Zeroes can be evaluated by, putting , y=0
→x(x-2)(x+3)=0
→x=0, ∧ x-2=0 ∧ x +3=0
→ x=0 ∧ x=2, ∧ x= -3
So, x=0, 2, -3 are zeroes of the cubic polynomial or the given function.
