Answer:
The area of the sector is [tex]12\pi[/tex]
Step-by-step explanation:
Given in the circle O,
Length of the radius = 12 units,
[tex]m\widehat{AB}=30^{\circ}[/tex]
We know that, the area of the sector is,
[tex]A=\dfrac{\theta}{360}\cdot \pi r^2[/tex]
Putting the values,
[tex]A=\dfrac{30}{360}\cdot \pi (12)^2[/tex]
[tex]=\dfrac{1}{12}\cdot \pi \cdot 144[/tex]
[tex]=12\pi[/tex]
Therefore, the area of the sector is [tex]12\pi[/tex]
