Respuesta :


[tex]2y = 10x \\ y = 10x \div2 = 5x[/tex]
[tex] \frac{ {x}^{2} }{64} - \frac{y^{2} }{36} = 1 \\ \frac{ {x}^{2} }{64} - \frac{(5x)^{2} }{36} = 1 \\ \frac{ {x}^{2} }{64} - \frac{25x^{2} }{36} = 1 [/tex]
A

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