1) 90°+41°=131° angles in a triangle add up to 180. 180-131=49°
B=49°
2) Let 41° be A and 24 be a
a/SinA=b/SinB
24/Sin41=b/Sin49
[tex]b = \frac{24 \times \sin(49) }{ \sin(41) } [/tex]
b=27.60884177
=27.6 (to 1 d.p.)
3)
a/SinA=c/SinC
[tex]c = \frac{24 \times \sin(90) }{ \sin(41) } [/tex]
c=36.58207408
=36.6 (to 1 d.p.)
