The  limiting  reagent  is  H₂SO₄
  calculation
Step 1 :write the equation for reaction
2 NaOH + H₂SO₄  → Na₂SO₄  + 2 H₂O
Step  2: use the mole ratio to determine the  moles of product  produced from each reactant
that is  from  equation above,
NaOH : Na₂SO₄  is 2 :1 therefore the  moles of Na₂So₄
= 10.0 moles x 1/2 = Â 5.0 moles
H₂SO₄ :Na₂SO₄  is 1:1 therefore the moles  of Na₂SO₄  is also = 3.50 moles
H₂SO₄  is the limiting reagent since  it produces  less amount of Na₂SO₄
