Respuesta :

camiccc99
[tex]3x + 2 \leqslant 5(x - 4) \\ 3x + 2 \leqslant 5x - 20 \\ 2 + 20 \leqslant 5x - 3x \\ 22 \leqslant 2x \\ \frac{22}{2} \leqslant x \\ 11 \leqslant x[/tex]

Answer:

x ≥ -11

ABOUT THIS ≤ INEQUALITY SIGN:

  • Less than/Equal to
  • No more than
  • At Most
  • Maximum of

3x + 2 ≤ 5(x - 4)

3x + 2 ≤ 5x - 20

-5x        -5x

-2x + 2 ≤ -20

      - 2    -2

-2x ≤ 22

-2        -2

x ≥ -11


Hope this helps you!!! :)



good job