Respuesta :

AlbertThomas
If we let g(x) = x + 2, then
[tex] {(x + 2)}^{2} + 2 = ( {x}^{2} + 4x + 4) + 2 \\ = {x}^{2} + 4x + 6[/tex]
Of course if we let f(x) = x + 2, then

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good job