Answer:
[tex]\displaystyle\sqrt[3]{2x}-6\sqrt[3]{x}[/tex]
Step-by-step explanation:
[tex]7\sqrt[3]{2x}-3\sqrt[3]{16x}-3\sqrt[3]{8x}=7\sqrt[3]{2x}-3\sqrt[3]{8}\sqrt[3]{2x}-3\sqrt[3]{8}\sqrt[3]{x}\\\\=7\sqrt[3]{2x}-3\cdot 2\sqrt[3]{2x}-3\cdot 2\sqrt[3]{x}=(7-6)\sqrt[3]{2x}-6\sqrt[3]{x}\\\\=\sqrt[3]{2x}-6\sqrt[3]{x}[/tex]
