chapulin68 chapulin68

10-01-2019
Mathematics

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What is the tru solution to the logarithmic equation below? Log4[log4(2x)]=1

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LammettHash LammettHash

10-01-2019

[tex]\log_4(\log_42x)=1[/tex]

Take both sides as powers of 4:

[tex]4^{\log_4(\log_42x)}=4^1\implies\log_42x=4[/tex]

Do it again:

[tex]4^{\log_42x}=4^4\implies2x=(2^2)^4=2^8\implies x=2^7=128[/tex]

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