Answer:
We are asked to show the graph of the function.
[tex]f(x)=\dfrac{4x^3+6}{2+x}[/tex]
clearly from the representation of the function we could see that the function has asymptote at x=-2 since the denominator is zero at that point i.e. the function is not defined at that point.
Also when x→ ∞, the graph of the function f(x)→ ∞
and when x→ -∞, the graph of the function f(x)→ ∞
Hence, the function f(x) is not bounded on the real line.
The graph is attached to the answer.
