Answer:
J 1
--------
x^2 -x
Step-by-step explanation:
x+1
----------
x^3-x
Factor out an x in the denominator
x+1
----------
x(x^2-1)
We can factor the terms in the parentheses because it is a difference of squares
x+1
----------
x(x-1) (x+1)
Canceling the x+1 terms
1
----------
x(x-1)
Distribute in the denominator
1
--------
x^2 -x
