Answer:
54
$3 dollar coupons were given
Step-by-step explanation:
We can represent this question as a system of equations
Let
x = number of $1 dollar coupons
y = number of $3 dollar coupons
z = number of $5 dollar coupons
Twice as many $1 coupons were given out as $3 coupons,
x = 2*y
3 times as many $3 coupons were given as $5 coupons.
y = 3*z
The total value of all the coupons given out was $360
x*$1 + y*$3 + z*$5 = $ 360
The system results
x  -  2y  +  0   =  0     (1)
0  +  y   -  3z   = 0     (2)
x   + 3*y    +5*z =  $ 360   (3)
We substitute  equation (2) and (1) into (3)
(2y)  + 3*y   + 5*(y/3) =  $ 360
20*y/3 Â = 360
y = 54
