Answer:
[tex]\frac{DE}{PQ}=\frac{3}{2}[/tex]
Step-by-step explanation:
we know that
If two triangles are similar, then the ratio of its corresponding sides is proportional
In his problem
If Triangles DEF and PQR are similar
then
The corresponding sides are
DF and PR
FE and RQ
DE and PQ
so
[tex]\frac{DF}{PR}=\frac{FE}{RQ}=\frac{DE}{PQ}=\frac{3}{2}[/tex]
