Answer:
p = 2 p = -4
Step-by-step explanation:
Find the solution for p^2+2p-8=0
using the Quadratic Formula where
a = 1, b = 2, c = -8
p = -b ±√(b^2 - 4ac)/2a
p = -2±√(2^2 - 4(1)(-8))/2(1)
p = -2±√(4 - (-32))/2
p = -2±√(36)/2
The discriminant b^2 - 4ac > 0
So, there are two roots.
Simplifying the radical
p = -2±6/2
p = -2+6/2 = 2
and
p = -2-6/2 = -4
