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10-05-2019
Chemistry

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Calculate the pH of a solution with [OH−]=1.3×10−2M. (Hint: Begin by using Kw to find [H3O+].)

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superman1987 superman1987

10-05-2019

Answer:

12.11.

Explanation:

∵ pOH = - log[OH⁻]

∴ pOH = - log(1.3 x 10⁻²) = 1.886.

∵ pH + pOH = 14.

∴ pH = 14 - pOH = 14 - 1.886 = 12.11.

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