Answer:
[tex]\large\boxed{(3x-7)(3x-5)=9x^2-36x+35}[/tex]
Step-by-step explanation:
[tex]\text{Use FOIL:}\ (a+b)(c+d)=ac+ad+bc+bd\\\\(3x-7)(3x-5)\\\\=(3x)(3x)+(3x)(-5)+(-7)(3x)+(-7)(-5)\\\\=9x^2-15x-21x+35\qquad\text{combine like terms}\\\\=9x^2+(-15x-21x)+35\\\\=9x^2-36x+35[/tex]
