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  • 06-06-2019
  • Mathematics
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Find the focus for y=x^2+4x-7

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kudzordzifrancis
kudzordzifrancis kudzordzifrancis
  • 06-06-2019

ANSWER

[tex](2,-10.75)[/tex]

EXPLANATION

The given function is

[tex]y = {x}^{2} - 4x - 7[/tex]

We rewrite this function to obtain,

[tex](y + 11) = {( x- 2)}^{2} [/tex]

We now compare this function to

[tex](y - k) = 4p {( x- h)}^{2} [/tex]

We have

[tex]4p = 1[/tex]

This implies that,

[tex]p = \frac{1}{4} [/tex]

The vertex is (2,-11).

The focus is

[tex](2,-11+ \frac{1}{4} )[/tex]

[tex](2,- \frac{43}{4} )[/tex]

[tex](2,-10.75)[/tex]

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