Vanessabradshaw2904 Vanessabradshaw2904
  • 07-06-2019
  • Chemistry
contestada

300 moles of sodium nitrite are needed for a reaction. the solution is 0.450 m. how many ml are needed?

Respuesta :

znk
znk znk
  • 07-06-2019

Answer:

[tex]\boxed{\text{667 000 mL}}[/tex]

Explanation:

[tex]\text{Molar concentration} = \dfrac{\text{moles}}{\text{litres}}\\\\c = \dfrac{n}{v}[/tex]

Data:

c = 0.450 mol·L⁻¹

n = 300 mol

Calculation:

[tex]\begin{array}{rcl}0.450 & = & \dfrac{300}{V}\\\\0.450V& = & 300\\\\V & = & \dfrac{300}{0.450}\\\\V & = & \text{667 L} =\textbf{667 000 mL}\end{array}\\\text{The volume of solution needed is }\boxed{\textbf{667 000 mL}}[/tex]

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