Answer:
(2y-1/y_2)(3y_2/7)
= 2y*(3y_2/7) - (1/y_2)(3y_2/7)
= 6y*y_2/7 - 3/7 = (6y*y_2 - 3)/7
Note: I'm not sure if the 2y-1 was written correctly. If it were intended as the entire thing being a numerator or as 2y_1, this answer is inaccurate.
Answer:
(6y-3)/7
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Step-by-step explanation:
(2y-1/y²)(3y²/7) first simplify 3y²/y² =3
(2y-1)(3/7) =
(6y-3)/7
