Answer:
let the equal sides of the triangle be of length "a" Β . let the angle between these two sides be " x Β ". Then drop a perpendicular from the vertex to the base. Β now u have 2 similar triangles Β .the angle between the perpendicular and one of the equal sides is now (x/2) Β . length of perpendicular = a cos(x/2) Β length of base = 2a sin(x/2) Β . area of triangle = (1/2) 2sin(x/2) cos(x/2) a-square Β
= (1/2) (sin x) a-square