[tex]\bf \textit{Logarithm Cancellation Rules} \\\\ log_a a^x = x\qquad \qquad \stackrel{\textit{we'll use this one}}{a^{log_a x}=x} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ e^{\ln(3x)}\implies e^{\log_e(3x)}\implies 3x[/tex]
Answer:
3x
Step-by-step explanation:
e^ln3x
We know that e and ln are inverses of each other, so when we take e to the power ln, they cancel
e^ ln 3x
3x
