Answer:
17.84 m/s
56.31 deg
Explanation:
Consider east direction along positive x-direction and north direction along positive y-direction.
mā = mass of car 1 = 1100 kg
vā = initial velocity of car 1 = 0 i + 31 j
mā = mass of car 2 = 1200 kg
vā = initial velocity of car 2 = 19 i + 0 j
v = final velocity of the combination of cars after collision
using conservation of momentum
mā vā + mā vā = (mā + mā ) v
(1100) (0 i + 31 j ) + (1200) (19 i + 0 j) = (1100 + 1200) v
34100 j + 22800 i = 2300 v
v = 9.91 i + 14.83 j
magnitude of the velocity is given as
|v| = sqrt(9.91² + 14.83²)
|v| = 17.84 m/s
Angle is given as
Īø = tanā»Ā¹(14.83/9.91)
Īø = 56.31 deg