Answer:
[tex]f^{-1}(x)=(1/6)x-(1/2)[/tex]
Step-by-step explanation:
we have
[tex]f(x)=6x+3[/tex]
Find the inverse function [tex]f^{-1}(x)[/tex]
step 1
Let
y=f(x)
[tex]y=6x+3[/tex]
step 2
Exchanges variables, x for y and y for x
[tex]x=6y+3[/tex]
step 3
isolate the variable y
[tex]x=6y+3[/tex]
[tex]6y=x-3[/tex]
[tex]y=(1/6)x-(1/2)[/tex]
step 4
Let
[tex]f^{-1}(x)=y[/tex]
[tex]f^{-1}(x)=(1/6)x-(1/2)[/tex]
