mariealicia22 mariealicia22

08-09-2019
Mathematics

contestada

Solve the equation on the interval [0, 2π).
tan^2x sin x = tan^2x

A. π/2, π
B. 0, π/2
C. 0, π
D. π/2, 2π

Respuesta :

thedemon840 thedemon840

09-09-2019

Answer:

x = pi/2..only

Step-by-step explanation:

The equation states that...,

tan^2x.sin x = tan^2x

;we simplify the equation by dividing both sides by tan^2x...which then leaves our equation as,

; sin x = 1

; x = sin^-1 (1)

; Hence x = pi/2

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