Answer:
[tex]\dfrac{27}{16}x^2[/tex]
Step-by-step explanation:
The relevant properties are ...
(a^b)^c = a^(bc)
(a^b)/(a^c) = a^(b-c)
So, the expression simplifies to ...
[tex]\dfrac{(3x^2)^3}{(2x)^4}=\dfrac{3^3x^{2\cdot 3}}{2^4x^4}=\dfrac{27}{16}x^{6-4}=\dfrac{27}{16}x^{2}[/tex]
