Answer:
y+3=-2(x-5)
Step-by-step explanation:
The point slope form is y-y1=m(x-x1) where m= slope and y1 and x1 are your point.
[tex]\bf (\stackrel{x_1}{5}~,~\stackrel{y_1}{-3})~\hspace{10em} \stackrel{slope}{m}\implies -2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{-2}(x-\stackrel{x_1}{5})\implies y+3=-2(x-5)[/tex]
