A 5.00-m-long uniform ladder, weighing 200 N, rests against a smooth vertical wall with its base on a horizontal rough floor, a distance of 1.20 m away from the wall. The coefficient of static friction between the ladder and the floor is 0.200. How far up the ladder, measured along the ladder, can a 600-N person climb before the ladder begins to slip

Respuesta :

Answer:

0.488 Ā m Ā 

Explanation:

If Īø be the angle ladder makes with the plane

cos Īø = 1.2 / 5

Tan Īø = 4.04

Let the height a person of weight 600 N Ā can climb be h from the ground .

Distance from the base point Ā where ladder touches the floor Ā = h / tanĪø

= h / 4.04

Total reaction force = total downward force

R = 200 + 600

800 N

Frictional force = μ R

= .2 x 800

= 160 N

Taking moment of force about the point on the ladder Ā where it Ā touches the floor Ā and balancing them

200 x 1.2 x .5 + 600 x Ā  h / tanĪø Ā = μ R x Ā 1.2 / tanĪø ( reaction Ā at the top point of ladder where it touches the wall is Ā R₁ and

R₁ =μ R Ā  )

= 200 x 1.2 x .5 + 600 x Ā  h / tanĪø Ā = 160 x 1.2 / tanĪø

120 Ā - 600 h / 4.04 = 47.52

120 - 47.52 = 600 h / 4.04

72.48= 148.51 h

h = 0.488 Ā m Ā 

=

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