Answer:
a) atoms Pb = 4.3595 E22 amu
b) g = ( 6.022 E23 amu ) Γ ( Mw )
Explanation:
sample:
β΄ m = 15.00 g
a) atoms Pb = ?
β atoms Pb = (15.00g Pb)(mol Pb/207.2 g)(6.022 E23 amu/mol)
β atoms Pb = 4.3595 E22 amu
b) relationship:
β΄ 1 mol (n) β‘ 6.022 E23 amu......(1)
β΄ mass (g) β‘ (Mw)Γ(n)
β n = g / Mw..........(2)
β΄ Mw: molecular weight
(1) = (2):
β g / Mw β‘ 6.022 E23 amu
β g β‘ ( 6.022 E23 amu ) Γ ( Mw )