Answer:
Step-by-step explanation:
[tex]\frac{3-4x}{6} -\frac{2x-3}{8} \geq \frac{2-x}{1} \\L.C.M. ~of~6~,1~and~8=24\\multiply ~by~24\\4(3-4x)-3(2x-3)\geq 24(2-x)\\12-16x-6x+9\geq 48-24x\\21-22x\geq 48-24x\\24x-22x\geq 48-21\\2x\geq 27\\x\geq \frac{27}{2} \\or~x\geq 13.5[/tex]
