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Which system of inequalities has no solution?

A. y < 2x − 4
y > 2x + 1

B. 2x + y ≥ 3
y ≥ −2x − 3

C. 4x + 4y < 16
x > y + 16

D. y < −6x −24
y < 6x + 6
Part B
Select all the possible ways that you could change the system so it has a solution.
A. Change the direction of the inequalities.
B. Decrease the coefficient of x in the first equation.
C. Increase the coefficient of x in the first equation.
D. Increase the coefficient of x in the second equation.
E. Decrease the coefficient of x in the second equation.

Respuesta :

Answer:A i think

Step-by-step explanation:

These are the following steps to find the no solution for the given inequalities.

Part 1 ; Given Equation ;   y < 2x-4

                                          y > 2x+1

From the equation 2 putting the value of y in equation 1

= 2x+1 = 2x-4

=  2x-2x = -4-1

=  0 = -5

The given equation has no solution.

Equation; 2x + y ≥ 3

                 y ≥ −2x − 3

From the equation 2 putting the value of y in equation 1

= 2x-2x-3 = 3

= 0= 3+3

= 0 = 0

So , the given equation has no solution.

Equation ;  4x + 4y < 16

                   x > y + 16

From the equation 2 putting the value of x in equation 1

 = 4( y + 16 ) + 4y = 16

 = 4y+ 64 + 4y = 16

= 8y = 16-64

= 8y = -48

= y = [tex]\frac{-48}{8}[/tex]

= y = -6

Put y=-6

Then x = -6 + 16

x = 10

The equation has solution x = 10 and y = -6 .

Equation ;   y < −6x −24

                   y < 6x + 6

Put the value of y in the equation 1 from equation 2

= 6x + 6 = -6x - 24

= 12x = -30

=  x = [tex]\frac{-30}{12}[/tex] = [tex]\frac{-15}{6}[/tex]

Put the value of x in the equation 1

y =  ([tex]-6(\frac{-15}{6}) - 24[/tex]

y = 15 - 24

y = -9

The equation has solution y = -9 and x =[tex]\frac{-15}{6}[/tex].

The First and second system of inequalities are correct which has no solution.

For more information about system of inequalities click the link given below

https://brainly.com/question/19935456

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