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Use the data table to answer the questions below Mass of
evaporating dish.......... ..................12.07g Mass of
evaporating dish plus hydrate.....................15.12 g Mass of
evaporating dish and anhydrous crystals ......13.58g
If the hydrate used in the lab for the above data table is
MgSO4.7H20, then calculate the theoretical % water in the hydrate
15%
51%
73%
95%
100%

Respuesta :

Answer:

Option B is correct : 51%

Explanation:

Data Given:

Hydrates used in lab = MgSOâ‚„ .7Hâ‚‚O

% water in hydrate = ?

Solution:

As we look for the the theoretical % water in hydrates

So

  • First of all find the atomic masses of each component in a molecule

For Hâ‚‚O atomic masses are given below

H = 1 g/mol

O = 16 g/mol

Then find the total mass of Hâ‚‚O in hydrated salt

           7H₂O = 7 (2x1 +1x16) g/mol

           7H₂O = 7 (2+16) g/mol

           7H₂O = 7 (18) g/mol

  •    7Hâ‚‚O = 126 g/mol

Now,

> find total Molar Mass of Molecule:

       Molar Mass of MgSO₄ • 7H₂O = [24 + 32 + 16x4] + 7(2+16)

       Molar Mass of MgSO₄ • 7H₂O = [24+ 32 + 64] + 126

       Molar Mass of MgSO₄ • 7H₂O = [120] + 126

  • Molar Mass of MgSOâ‚„ • 7Hâ‚‚O = 246 g/mol

Now to find the mass by percent of (water) Hâ‚‚O

Formula used to find the mass by percent of a component

Percent composition of H₂O = mass of H₂O in Molecule / molar mass of MgSO₄•7H₂O x 100%

Put the values in above formula

        Percent by mass of H₂O = 126 (g/mol) / 246 (g/mol) x 100%

        Percent by mass of H₂O = 0.51 x 100%

        Percent by mass of H₂O = 51%

So,

Option B is correct : 51%

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