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  • 07-02-2020
  • Mathematics
contestada

Find the product of -3x^3+2x-4 and x^3+x-2​

Respuesta :

calculista
calculista calculista
  • 13-02-2020

Answer:

[tex]-3x^6-x^4+2x^3+2x^2-8x+8[/tex]

Step-by-step explanation:

we have

[tex](-3x^{3}+2x-4)(x^{3}+x-2)[/tex]

Applying distributive property

[tex](-3x^3)(x^3)+(-3x^3)(x)+(-3x^3)(-2)+(2x)(x^3)+(2x)(x)+(2x)(-2)+(-4)(x^3)+(-4)(x)+(-4)(-2)[/tex]

Remember the properties

[tex](-1)(-1)=(+1)\\(-1)(+1)=(-1)[/tex]

[tex]x^{m}x^{n}=x^{m+n}[/tex]

so

[tex](-3x^6)+(-3x^4)+(6x^3)+(2x^4)+(2x^2)+(-4x)+(-4x^3)+(-4x)+(8)[/tex]

Combine like terms

[tex]-3x^6-x^4+2x^3+2x^2-8x+8[/tex]

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