ctsinijinni ctsinijinni

08-02-2020
Mathematics

contestada

find three consecutive odd integers such that the product of the first and third is 71 more than 10 times the second

Respuesta :

Aaqib10 Aaqib10

08-02-2020

Answer:

13, 15, 17

Step-by-step explanation:

x(x + 4) = 10(x + 2) + 71

x2 + 4x = 10x + 20 + 71

x2 - 6x - 91 = 0

(x + 7)(x - 13) = 0

x + 7 = 0

x = -7

-7, -5, -3

x - 13 = 0

x = 13

13, 15, 17

Answer Link

Otras preguntas

1. Name the three particles of the atom and their respective charges:

Karina has an inflammatory disease of her gastrointestinal tract that causes her to experience cramps, joint pain, and diarrhea. her diagnosis is

-2=7-m/3, How would I solve that?

You have $100 in your lunch account and plan to spend $2.75 each school day. how many school days will it take to spend all of the money in your account?

1) Which statements accurately describe Isaac Newton's achievements? Choose all that are correct. (A) He discovered white light was made up of the many differe

Tammy decorated her art project with 12 different colors of sequins if she used 15 of each color how many sequins did tammy use

Write a metaphor about someone’s hair

what causes platelets to become sticky platelets

Can someone explain this : How did men felt on how women got the right to vote

Descompuneti in factori. x^2+4x-5=?

good job