Answer:
given, mother and father are heterozygotes.
let, father has B blood group and mother has A blood group.
then their heterozygous  genotypes are --
father = iB, iO Â and mother = iA, iO
punnett square will be,
    iB     iO
iA Â Â iA iB Â Â iA iO
iO Â Â iB iO Â Â iO iO
the genotypes of their progeny will be, iAiB , Â iAiO ,iBiO and iOiO
and phenotypes will be 3 are heterozygous and 1 is homozygous.