Respuesta :
Answer:
The mass flow rate of CHâ‚„ is 0.0275 kg/s and the mass flow rate of air is 0.4725 kg/s
Explanation:
The molar masses are equal to:
MCHâ‚„ = 16.043 kg/kmol
MNâ‚‚ = 28.01 kg/kmol
MOâ‚‚ = 32 kg/kmol
MHâ‚‚O = 18.01 kg/kmol
MCOâ‚‚ = 44.01 kg/kmol
The combustion reaction is:
CHâ‚„ + a(Oâ‚‚ + 3.76Nâ‚‚) = COâ‚‚ + 2Hâ‚‚O + 3.76aNâ‚‚
The Oâ‚‚ balance is:
a = 1 + 1 = 2
CHâ‚„ + 2(Oâ‚‚ + 3.76Nâ‚‚) = COâ‚‚ + 2Hâ‚‚O + 7.52Nâ‚‚
The masses of the reactants are equal to:
mCHâ‚„ = nCHâ‚„ * MCHâ‚„ = 1 * 16.043 = 16.043 kg
mOâ‚‚ = nOâ‚‚ * MOâ‚‚ = 2 * 32 = 64 kg
mNâ‚‚ = nNâ‚‚ * MNâ‚‚ = 2 * 3.76 * 28.01 = 210.64 kg
mtotal = 16.043 + 64 + 210.64 = 290.683 kg
The masses fractions are equal to:
mfCHâ‚„ = 16.043/290.683 = 0.055
mfOâ‚‚ = 64/290.683 = 0.22
mfNâ‚‚ = 210.64/290.683 = 0.724
The mass flow rates of the reactants are equal to:
mfrCHâ‚„ = 0.055 * 0.5 = 0.0275 kg/s
mfrair = 0.5 - 0.0275 = 0.4725 kg/s
