Given:
Random survey of Scobey middle school
To find:
The percent of students like cookies.
Solution:
Total number of cookies = 49 + 12 + 10 + 8 + 3
                     = 82
Percentage formula:
[tex]$\text{Percentage of part} = \frac{\text{Part}}{\text{Whole} }\times 100[/tex]
[tex]$\text{Chocolate chip }\%=\frac{49}{82}\times100[/tex]
              = 59.76%
Percent of student like chocolate chip is 59.76%.
[tex]$\text{Peanut butter}\%=\frac{12}{82}\times100[/tex]
             = 14.64%
Percent of student like peanut butter is 14.64%.
[tex]$\text{Oatmeal}\%=\frac{10}{82}\times100[/tex]
        = 12.19%
Percent of student like oatmeal is 12.19%.
[tex]$\text{Sugar}\%=\frac{8}{82}\times100[/tex]
       = 9.76%
Percent of student like sugar is 9.76%.
[tex]$\text{Raisin}\%=\frac{3}{82}\times100[/tex]
       = 3.65%
Percent of student like raisin is 3.65%.
