Answer:
Q = 6450 j
Explanation:
Given data:
Mass of gold = 10 kg (10×1000 =10,000 g)
Initial temperature = 25°C
Final temperature = 30°C
Energy absorbed = ?
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
Specific heat capacity of gold = 0.129 j/g.°C
ΔT = 30°C - 25°C
ΔT = 5°C
Q = 10,000 g ×0.129 j/g.°C× 5°C
Q = 6450 j
