Answer:
11 grams of argon gas
Explanation:
PV = nRT
P= 18.4 atm
V = 50 L
n = find moles then use molar mass to convert to grams
R = atm gas constant = 8.314
T = IN Kelvins** = 127 C + 273 = 400 K
molar mass of Ar =40g / mol
18.4(50) = 8.314(400)n
n = .276 mol Ar
.276(40) = 11 grams of Argon Gas
