Respuesta :
Light shines through two polarizes. Initially, both transmission axes are aligned and then the second polarize is rotated while the other remains fixed
Explanation:
The Law of Malus gives the value of Ā transmitted intensity through two ideal polarizes. Also When we rotate Ā second polarizer , the vector component perpendicular to its transmission plane is absorbed, and Ā its amplitude Ā is reduced to
[tex]E=Ex_{0} Cos[/tex]Īø
let I be the intensity of transmitted light in the y-axis while the degrees in the x-axis Ā be -90, 180, 270, and 360.
For 0ā° transmitted intensity = cosĀ²(0ā°) = 1 (1st maximum on graph)
For 90ā° transmitted intensity = cosĀ²(90ā°) = 0 (1st minimum on graph)
For 180ā° transmitted intensity = cosĀ²(180ā°) = 1 (2nd maximum on graph)
For 270ā° transmitted intensity = cosĀ²(270ā°) = 0 (2nd minimum on graph)
For 360ā° transmitted intensity = cosĀ²(360ā°) = 1 (3rd maximum on graph)
According to the Malus Law, the intensity of the transmitted light will follow the curve defined by cosĀ²Īø, where Īø is the angle of rotation.
Malus Law:
According to Malus law if a light of intensity Iā is passed through a polarizer, the intensity I of the transmitted light is given by:
I = IācosĀ²Īø
where Īø is the angle between the axis of the polarizer and the direction of polarization of the light.
So if we graph the intensity of transmitted light on the y-axis and the angle of rotation of the polarizer on the x-axis,
such that the angle of rotation of the polarizer is Īø = 0, 90, 180, 270, and 360.
At 0ā°
I = IācosĀ²(0Ā°) = Iā (1st maximum on graph)
At 90ā°
I = IācosĀ²(90Ā°) = 0 (1st minimum on graph)
At 180ā°
I = IācosĀ²(180Ā°) = Iā (2nd maximum on graph)
At 270ā°
I = IācosĀ²(0Ā°) = 0 (2nd minimum on graph)
At 360ā°
I = IācosĀ²(360Ā°) = Iā Ā (3rd maximum on graph)
Learn more about Malus Law:
https://brainly.com/question/14177847?referrer=searchResults
