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Complete the table to investigate dilations of exponential functions. A 4-column table has 5 rows. The first column is labeled x with entries negative 2, negative 1, 0, 1, 2. The second column is labeled 2 Superscript x with entries one-fourth, one-half, a, d, 4. The third column is labeled 3 times 2 Superscript x with entries three-fourths, three-halves, b, e, 12. The fourth column is labeled 2 Superscript 3 x with entries StartFraction 1 Over 64 EndFraction, one-eighth, c, f, 64. a = b = c = d = e = f =

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Answer:

Step-by-step explanation:

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The values a , b, c,d, e, f are as follows

a=   1      b =   3        c= 1

d=  2      e =  6          f = 8  

The Exponential function A 4 columns and 5 Rows

Given

x          y= [tex]2^x[/tex]    z = 3([tex]2^x[/tex])   p = [tex]2^{3x}[/tex]

-2         1/4          3/4           1/64

-1         1/2          3/2            1/8

0          a          b                c

1           d           e                f

2          4            12            64

To be found the values of a , b, c, d, e , f

a  

b

c

d

e

f

Exponential function A  has 4 columns and 5 Rows

We can compare  

x          y= [tex]2^x[/tex]    z = 3([tex]2^x[/tex])   p = [tex]2^{3x}[/tex]

-2         1/4          3/4           1/64

-1         1/2          3/2            1/8

0          a=   1       b =   3        c= 1

1           d=  2      e =  6          f = 8  

2           4            12            64

hence

a=   1     b =   3        c= 1

d=  2      e =  6         f = 8  

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